4t-2+t=6+t^2

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Solution for 4t-2+t=6+t^2 equation:



4t-2+t=6+t^2
We move all terms to the left:
4t-2+t-(6+t^2)=0
We add all the numbers together, and all the variables
-(6+t^2)+5t-2=0
We get rid of parentheses
-t^2+5t-6-2=0
We add all the numbers together, and all the variables
-1t^2+5t-8=0
a = -1; b = 5; c = -8;
Δ = b2-4ac
Δ = 52-4·(-1)·(-8)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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